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Math Help - Using l'hospital's Rule

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    Using l'hospital's Rule

    Find lim x -> infinity ( x^(3) * e^(-x^2) )
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    Quote Originally Posted by TsAmE View Post
    Find lim x -> infinity ( x^(3) * e^(-x^2) )
     <br />
\lim_{x \to \infty} \frac{x^3}{e^{x^2}}<br />

     <br />
\lim_{x \to \infty} \frac{3x^2}{2x e^{x^2}}<br />

    \lim_{x \to \infty} \frac{3x}{2e^{x^2}}

    \lim_{x \to \infty} \frac{3}{4xe^{x^2}} = ?
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