Please help me.. dy + 7x dx = 0 Given y(0)=3
Last edited by cron1003; May 10th 2010 at 10:23 PM.
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Originally Posted by cron1003 Please help me.. dy + 7x dx = 0 assume dy(0)=3 Separable equation. dy(0)=3 or y(0)=3? $\displaystyle dy=-7xdx\rightarrow\int dy=-7\int xdx\rightarrow y=\frac{-7x^2}{2}+C_1$ If you mean y(0)=3, then C=3. $\displaystyle y=\frac{-7x^2}{2}+3$
Ops! you are correct. given y(0) = 3. this is correct.. sorry for my mistake.
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