Hi I have a few calculus questions, could you please explain how to get the final answer too, thanks. Derivative of : dy/dx here dy/dx here dy/dt here
Last edited by KK88; May 10th 2010 at 07:37 PM.
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Originally Posted by KK88 Hi I have a few calculus questions, could you please explain how to get the final answer too, thanks. Derivative of : Chain rule of the chain rule with a product rule chain rule dy/dx here chain rule dy/dx here product rule with chain dy/dt here chain You haven't attempted much so start by trying that.
Ok I figured out the middle three but I cannot quite get the first one and last one
$\displaystyle (cos\big(e^{x^2cos(x)}\big))^{\frac{1}{2}}$ $\displaystyle \frac{1}{2}(cos\big(e^{x^2cos(x)}\big))^{\frac{-1}{2}}(-sin\big(e^{x^2cos(x)}\big))(e^{x^2cos(x)}(2xcos(x)-x^2sin(x)))$ I am not going to simplify that.
$\displaystyle e^{2sin(8t)}$ $\displaystyle 8e^{2sin(8t)}2cos(8t)=16e^{2sin(8t)}cos(8t)$
Thanks for the responses. The second one is correct however I still cant get the first one right, I input this:
The first one is correct too. Here is the maple output.
$\displaystyle \frac{1}{2}(cos\big(e^{x^2cos(x)}\big))^{\frac{-1}{2}}(-sin\big(e^{x^2cos(x)}\big))(e^{x^2cos(x)}(2xcos(x)-x^2sin(x)))$ You need to have this quantity in parenthesis. (2xcos(x)-x^2sin(x))
Thanks that did it.
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