In general, how do you go about finding the limit of a sequence?

e.g. n^{1/ }

Sorry about latex fail, its n to the power the whole of the bracket.

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- May 10th 2010, 09:14 AMMathman87limits of a sequence
In general, how do you go about finding the limit of a sequence?

e.g. n^{1/ }

Sorry about latex fail, its n to the power the whole of the bracket. - May 10th 2010, 09:43 AMdwsmith
- May 10th 2010, 09:51 AMMathman87
It doesnt specify on the examples, but i imagine infinity?

- May 10th 2010, 09:53 AMdwsmith
is an indeterminant form. Do you know how to solve those?

- May 10th 2010, 09:57 AMMathman87
no?

- May 10th 2010, 10:01 AMdwsmith
L'Hopital's Rule

- May 10th 2010, 10:29 AMAllanCuz
- May 10th 2010, 10:33 AMMathman87
Ok, so can L'hopitals rule always be used to find the limit of sequences?

Like if i had {(2n+3)(3n+2)}/{(n^2)+3n+2} would the limit be 6?

Also if i had {log(n)}/{10th root of n}..... sorry latex fail again, would i be able to use L'hopitals rule this time? - May 10th 2010, 10:36 AMAllanCuz
- May 10th 2010, 10:46 AMMathman87
Ok i see. So i tried using L'hopitals rule for {log(n)}/{n^(1/10)}

So i differentiated the denominator and the numerator and ended up with 10*{n^(-1/10)}. Is this right?

Im not convinced im using it right lol! - May 10th 2010, 10:53 AMAllanCuz
- May 10th 2010, 11:36 AMMathman87
I know, but it doesnt tell us what n is tending towards on the question, hence why im a bit confused?

Iv attatched the document so you can see what i mean. Its question 4.... - May 10th 2010, 11:44 AMdwsmith
Since this is a test from 2007/2008, I would assume the prof. may have stated what the limits are approaching in class.

4

(i) is probably infinity and then the answer is e - May 10th 2010, 11:48 AMdwsmith
(iii) proabably 0

(iv)+(v)

AllanCuz answered

(ii) is probably supposed to be approaching infinity