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Math Help - Simple Harmonic Motion

  1. #1
    Senior Member
    Joined
    Jul 2008
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    Exclamation Simple Harmonic Motion

    A particle is moving with SHM of period pi seconds and maximum velocity 8 m/s. If the particle started from rest at x=a, find a, then find the velocity when the particle is distant 3 m from the mean position.


    So i did...

    Let motion be x =acosnt
    period = 2pi/n = pi
    hence, n = 2
    x = acos 2t ---------(1)
    v = -2a sin 2t
    For maximum velocity, sin 2t = -1.
    8 = -2a * -1
    a =4

    Am I right so far???

    I have no idea how to find the velocity . I thought i would let x = 3 and sub into one but I didnt get the answer provided.
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  2. #2
    Super Member
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    Use the relation

    v^2 = n^2( a^2 - x^2)
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