Hi all, your feedback appreciated. dx / 2x-x^2 = 1 / x(2-x) = 1/x . 1/2-x = 1/x dx + 1/(2-x) dx = In x + - In (2-x) + c = In x - In (2-x) + c Is this correct ???
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Originally Posted by Joel Hi all, your feedback appreciated. dx / 2x-x^2 = 1 / x(2-x) = 1/x . 1/2-x = 1/x dx + 1/(2-x) dx = In x + - In (2-x) + c = In x - In (2-x) + c Is this correct ??? $\displaystyle \frac{1}{x(2-x)} \ne \frac{1}{x} + \frac{1}{2-x}$ use partial fraction decomposition ... $\displaystyle \frac{1}{x(2-x)} = \frac{A}{x} + \frac{B}{2-x}$ solve for A and B
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