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Math Help - Can you please check my working...

  1. #1
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    Can you please check my working...

    Hi all, your feedback appreciated.

    dx / 2x-x^2

    = 1 / x(2-x)
    = 1/x . 1/2-x
    = 1/x dx + 1/(2-x) dx
    = In x + - In (2-x) + c
    = In x - In (2-x) + c

    Is this correct ???
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  2. #2
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    Quote Originally Posted by Joel View Post
    Hi all, your feedback appreciated.

    dx / 2x-x^2

    = 1 / x(2-x)
    = 1/x . 1/2-x
    = 1/x dx + 1/(2-x) dx
    = In x + - In (2-x) + c
    = In x - In (2-x) + c

    Is this correct ???
    \frac{1}{x(2-x)} \ne \frac{1}{x} + \frac{1}{2-x}



    use partial fraction decomposition ...

    \frac{1}{x(2-x)} = \frac{A}{x} + \frac{B}{2-x}

    solve for A and B
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