# Math Help - Can you please check my working...

1. ## Can you please check my working...

dx / 2x-x^2

= 1 / x(2-x)
= 1/x . 1/2-x
= 1/x dx + 1/(2-x) dx
= In x + - In (2-x) + c
= In x - In (2-x) + c

Is this correct ???

2. Originally Posted by Joel

dx / 2x-x^2

= 1 / x(2-x)
= 1/x . 1/2-x
= 1/x dx + 1/(2-x) dx
= In x + - In (2-x) + c
= In x - In (2-x) + c

Is this correct ???
$\frac{1}{x(2-x)} \ne \frac{1}{x} + \frac{1}{2-x}$

use partial fraction decomposition ...

$\frac{1}{x(2-x)} = \frac{A}{x} + \frac{B}{2-x}$

solve for A and B