1. ## line point distance

Use dot product methods to find the distance from (5,2) to the line 2x-7y=0.

2. Originally Posted by vvc531
Use dot product methods to find the distance from (5,2) to the line 2x-7y=0.
I don't know about dot product methods, but note that the line can be rewritten as $y = \frac{2}{7}x$.

That means you're wanting to find the minimum distance between $(5, 2)$ and $\left(x, \frac{2}{7}x\right)$.

The distance between these points is:

$D = \sqrt{\left(x - 5\right)^2 + \left(\frac{2}{7}x - 2\right)^2}$

$= \sqrt{x^2 - 10x + 25 + \frac{4}{49}x^2 - \frac{8}{7}x + 4}$

$= \sqrt{\frac{53}{49}x^2 - \frac{78}{7}x + 29}$

$= \left(\frac{53}{49}x^2 - \frac{78}{7}x + 29\right)^{\frac{1}{2}}$.

You should now be able to find the minimum distance, by taking the derivative, setting equal to 0 and solving, then using the second derivative test.