Can somebody tell me how the denominator contains (2n+2)(2n+1) in the answer. I am thinking (2n)!/(2n+2)! expands into (2n)!/(2n)!(2n+2). This simplifies into 1/(2n+2).
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$\displaystyle \frac{(2n)!}{(2n+2)!} = \frac{(2n)!}{(2n+2)(2n+1)(2n)!} $
So it is. Many thanks.
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