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Math Help - Parabola - vertex, focus, directrix

  1. #1
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    Parabola - vertex, focus, directrix

    The equation below represents a parabola:

    y^2+2y+1=16x-96

    Find:

    1) the coordinates of the vertex (xc,yc)
    2) the coordinates of the focus (xf,yf)
    3) and the equation of the directrix

    I don't know where to even begin to solve this.
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  2. #2
    MHF Contributor
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    Quote Originally Posted by aspotonthewall View Post
    The equation below represents a parabola:

    y^2+2y+1=16x-96

    Find:

    1) the coordinates of the vertex (xc,yc)
    2) the coordinates of the focus (xf,yf)
    3) and the equation of the directrix

    I don't know where to even begin to solve this.
    firstly , put it in the form of its general equation , y^2=4ax

    (y+1)^2=4(4)(x-6)

    The vertex is (-1,6)

    focus=(a,0) where a=4

    and the equation of directric is x=-a
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