The equation below represents a parabola: Find: 1) the coordinates of the vertex (xc,yc) 2) the coordinates of the focus (xf,yf) 3) and the equation of the directrix I don't know where to even begin to solve this.
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Originally Posted by aspotonthewall The equation below represents a parabola: Find: 1) the coordinates of the vertex (xc,yc) 2) the coordinates of the focus (xf,yf) 3) and the equation of the directrix I don't know where to even begin to solve this. firstly , put it in the form of its general equation , y^2=4ax (y+1)^2=4(4)(x-6) The vertex is (-1,6) focus=(a,0) where a=4 and the equation of directric is x=-a
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