Parabola - vertex, focus, directrix

The equation below represents a parabola:



Find:

1) the coordinates of the vertex (xc,yc)
2) the coordinates of the focus (xf,yf)
3) and the equation of the directrix

I don't know where to even begin to solve this.

Quote:

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Originally Posted by aspotonthewall

The equation below represents a parabola:



Find:

1) the coordinates of the vertex (xc,yc)
2) the coordinates of the focus (xf,yf)
3) and the equation of the directrix

I don't know where to even begin to solve this.

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firstly , put it in the form of its general equation , y^2=4ax

(y+1)^2=4(4)(x-6)

The vertex is (-1,6)

focus=(a,0) where a=4

and the equation of directric is x=-a