yes that is correct .Hey,

I have the questions

"Find the equation to the tangent line of the curve"

x^3 + y^3 = 6xy at point (3, 3)

sooo

i make it a quadratic, differentiate, and i know i did all this good, but i just want to double check, first ill write out what i did.

so i got

3x^2 + 3y^2y' -6y -6xy'

plug in 3's to get y' = -1

then do i put that into the equatoin of a line

using y' as the gradient?

so it would be y = -x + c

plug in 3's and get

y = -x + 6

for the equation of the tangent line?