yes that is correct .Hey,
I have the questions
"Find the equation to the tangent line of the curve"
x^3 + y^3 = 6xy at point (3, 3)
i make it a quadratic, differentiate, and i know i did all this good, but i just want to double check, first ill write out what i did.
so i got
3x^2 + 3y^2y' -6y -6xy'
plug in 3's to get y' = -1
then do i put that into the equatoin of a line
using y' as the gradient?
so it would be y = -x + c
plug in 3's and get
y = -x + 6
for the equation of the tangent line?