How do you find the area bounded by
y= 4x^3 and y= 12x^2-8x
The graphs intersect three times. If you solve you find that they intersect at
So you will have to use two integrals. The cubed function is greater than the parabola on the interval and the parabola is greater on the interval from . This is obvious if you graph it on a calculator. Or you can just use test values. The area should be: