can someone help me solve

integral from 0 to 4 of

(x)/ (square root of x^2+9) dx

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- May 6th 2010, 03:59 AMcummings15definite integral problem
can someone help me solve

integral from 0 to 4 of

(x)/ (square root of x^2+9) dx - May 6th 2010, 04:06 AMpiglet
- May 6th 2010, 04:06 AMskeeter
- May 6th 2010, 04:10 AMFailure
- May 6th 2010, 04:20 AMcummings15
so far i got

u=x^2+9

du=2xdx

(1/2)du=xdx

so i pluged it in and got

(1/2) integral of (du/u)

what do i do with the 0 to 4 part? - May 6th 2010, 04:40 AMFailure
No, that's not quite correct, you should have

Quote:

what do i do with the 0 to 4 part?

or you can do a back-substitution before you apply the old limits: