can someone solve ∫ square root of (9-4x^2dx)
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Originally Posted by cummings15 can someone solve ∫ square root of (9-4x^2dx) How about Substituting , thus and . This gives you and, maybe, you kow how to solve this last integral...
i think the final answer is (2/3)(9-4x^2)(3/2) + C
Originally Posted by cummings15 i think the final answer is (2/3)(9-4x^2)(3/2) + C No, I don't think so, because you have which is perhaps a little more complicated than you thought.
ok so i tried solving that and i got (9/4)arcsin(2x/3)+2x(square root of 9-4x^2)+c
Originally Posted by cummings15 ok so i tried solving that and i got (9/4)arcsin(2x/3)+2x(square root of 9-4x^2)+c Why don't you just use Wolfram Mathematica Online Integrator to check your result? - If it is not quite correct, then at least it is close...
here are my choices 2/3(9-4x^2)^3/2 + C 1/3tan^-1(2x/3)+c square root of (9-4x^2)^3/2 divided by 8x 9/4arcsin(2x/3) + 2x square root of (9-4x^2) + C i think it is either the first or last choice it didn't show up in wolfram
Originally Posted by cummings15 here are my choices 2/3(9-4x^2)^3/2 + C 1/3tan^-1(2x/3)+c square root of (9-4x^2)^3/2 divided by 8x 9/4arcsin(2x/3) + 2x square root of (9-4x^2) + C i think it is either the first or last choice I get (as does Wolfram's Integrator): it didn't show up in wolfram Well, you have to enter the integrand first: I could not get a link to the result because that particular link got mangled when I tried to insert it into my post.
Originally Posted by cummings15 can someone solve ∫ square root of (9-4x^2dx) hi or make a substitution of x=3/2 sin theta
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