can someone solve
lim (sin4x)/(x^2+8x)
x approaches 0
A little more basic method:
cummings15, rewrite it as $\displaystyle \frac{sin(4x)}{x^2+ 8x}= \frac{sin(4x)}{x(x+ 8)}$$\displaystyle = 4\frac{sin(4x)}{4x}\frac{1}{x+ 8}$.
Now, if you know the $\displaystyle \lim_{\theta\to 0}\frac{sin(\theta)}{\theta}$, this is easy.