Average Value of a Number

Can someone please help me out with this problem? It is the last one I have for my calculus assignment due tomorrow! We haven't done anything like this in class, so I have NO idea what to do.

Here is a link to a picture of the problem because I couldn't type it on here.

http://img3.imageshack.us/img3/5082/mathfp5.jpg

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Originally Posted by JollyJolly15

Can someone please help me out with this problem? It is the last one I have for my calculus assignment due tomorrow! We haven't done anything like this in class, so I have NO idea what to do.

Here is a link to a picture of the problem because I couldn't type it on here.

http://img3.imageshack.us/img3/5082/mathfp5.jpg

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The average value of a Riemann-integrable functuon over an interval is given by

In your case, note that , so the integral of that function is pretty easy...(Wink)

Tonio

we should do differentiation or integration??
if its deferenciation then
use the product principle rule (Cool)
e^3tanx+1 * d/dx sec^2x + sec^2x * d/dx e^3tanx+1
= e^3tanx+1 * 2secx(secxtanx) + sec^2x * e^3tanx+1(3sec^2x)
then simplyfy it and substitute x as 0 and x as 45 and then add the values and divide them by 2,
you will get the answer

Quote:

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Originally Posted by grgrsanjay

we should do differentiation or integration??
if its deferenciation then
use the product principle rule (Cool)
e^3tanx+1 * d/dx sec^2x + sec^2x * d/dx e^3tanx+1
= e^3tanx+1 * 2secx(secxtanx) + sec^2x * e^3tanx+1(3sec^2x)
then simplyfy it and substitute x as 0 and x as 45 and then add the values and divide them by 2,
you will get the answer

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Tonio had already said that it was an integration

If you needed to find the average of a finite list of numbers, you would add them all up and divide by the "number of numbers". With a continuous function that "adding" becomes integrating.