1. ## Inverse trig integration

I have the function

$1/\sqrt{4-3x^2}$

and I see that it is in the form of arcsin. Where do I go from here? I know arctan has a little trick where the integral is

$(1/a) arctan (x/a)$

Does arcsin have a similar trick? How would you solve this?

2. Originally Posted by Mattpd
I have the function

$1/\sqrt{4-3x^2}$

and I see that it is in the form of arcsin. Where do I go from here? I know arctan has a little trick where the integral is

$(1/a) arctan (x/a)$

Does arcsin have a similar trick? How would you solve this?
6. Integration: Inverse Trigonometric Forms

3. Originally Posted by skeeter
Thanks. It's even easier than the arctan form