can someone solve ∫ (4dx)/(x²-2x-3) i don't think this equation diverges i think the denominator is 10 and not 4 but i am not sure
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Originally Posted by cummings15 can someone solve ∫ (4dx)/(x²-2x-3) i don't think this equation diverges i think the denominator is 10 and not 4 but i am not sure let ... let ... now you can integrate the right side ...
Originally Posted by cummings15 can someone solve ∫ (4dx)/(x²-2x-3) i don't think this equation diverges i think the denominator is 10 and not 4 but i am not sure Now find and such that
would it be 4ln l(x-3)(x+1)l +c
No. Skeeter had already worked out that the coefficients A and B are 1 and -1 so the integral is 4(ln|x-3|- ln|x+1|)+ C.
so then i can distribute and get 4ln l(x-3)(x+1)l + C
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