can someone solve

∫9xcos(3x+1)dx

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- May 5th 2010, 03:27 PMcummings15integration by parts question
can someone solve

∫9xcos(3x+1)dx - May 5th 2010, 03:30 PMques
- May 5th 2010, 03:34 PMsurjectiveintegration
Hello,

Define the functions $\displaystyle f(x)=9x$ and $\displaystyle g(x)=\cos(3x-1)$.

Choose which function you would like to integrate and which one you would like to diferentiate. Then simply apply the formula:

$\displaystyle \int f(x)g(x)= F(x)g(x)-\int F(x)g'(x)$ - May 5th 2010, 03:40 PMskeeter
- May 5th 2010, 03:43 PMques
- May 5th 2010, 04:05 PMsurjectiveintegration
Hello,

The functions I defined were not meant to be fixed. You could just swop them around. I just wanted the basic idea to be understood, i.e. that you may choose either one of the function to integrate or differentiate, ofcourse selecting wisely. - May 5th 2010, 04:07 PMques
- May 5th 2010, 04:30 PMcummings15
thanks skeeter