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Math Help - need help with a dy/dx equation

  1. #1
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    need help with a dy/dx equation

    y= √x + ln(x)
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  2. #2
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    Quote Originally Posted by abii View Post
    y= √x + ln(x)
    (\ln x)' = \frac{1}{x} and (\sqrt{x})' = \frac{-1}{2\sqrt{x}}
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  3. #3
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    Quote Originally Posted by pickslides View Post
    (\ln x)' = \frac{1}{x} and (\sqrt{x})' = \frac{-1}{2\sqrt{x}} ... \textcolor{red}{\frac{+1}{2\sqrt{x}}} , typo?
    ...
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