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Math Help - Acceleration 2

  1. #1
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    Exclamation Acceleration 2

    The velocity of a particle starting at the origin is v = (cos2x)^2. Show that acceleration = -4(cos2x)^3 sin2x. When I differentiate v to get acceleration, i do not get the cubed part. Please help???
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  2. #2
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    Quote Originally Posted by Sunyata View Post
    The velocity of a particle starting at the origin is v = (cos2x)^2. Show that acceleration = -4(cos2x)^3 sin2x. When I differentiate v to get acceleration, i do not get the cubed part. Please help???
    a = \frac{d}{dt} [\cos(2x)]^2

    a = 2[\cos(2x)] \cdot [-\sin(2x)] \cdot 2 \cdot \frac{dx}{dt}

     <br />
a = 2[\cos(2x)] \cdot [-\sin(2x)] \cdot 2 \cdot \cos^2(2x)<br />

    simplify ...
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