Can anyone show the following:
$\displaystyle N^N$$\displaystyle e^{-N}$ $\displaystyle \leq$ $\displaystyle e^{-1}$ x N! $\displaystyle \leq$ N x $\displaystyle N^N$$\displaystyle e^{-N}$
N.B. The "x" are multiplication signs
Can anyone show the following:
$\displaystyle N^N$$\displaystyle e^{-N}$ $\displaystyle \leq$ $\displaystyle e^{-1}$ x N! $\displaystyle \leq$ N x $\displaystyle N^N$$\displaystyle e^{-N}$
N.B. The "x" are multiplication signs