Prove that has a limit: The subject is integrals, Riemann's definition and all that... I have no idea how to look for a solution Thanks!
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Originally Posted by adam63 Prove that has a limit: The subject is integrals, Riemann's definition and all that... I have no idea how to look for a solution Thanks! Step 1:: Take d = i/2^(n+1) Use 2 sin a . cos a = sin 2a For example, 2 sin i/2^k . cos i/2^k = sin i/2^(k-1) Step 2 :: Then use Comparision Test with series 1/2^(n+1)
Last edited by ques; May 5th 2010 at 03:14 PM.
Originally Posted by ques Step 1:: Take d = i/2^(n+1) Use 2 sin a . cos a = sin 2a For example, 2 sin i/2^k . cos i/2^k = sin i/2^(k-1) Step 2 :: Then use Comparision Test with series 1/2^(n+1) --- Well.. it looks like an optimal solution, but I am looking for a solution that involves use of integrals, and the Riemann's definition of integrals. Something like
Can anyone please help me with that? I need it urgently.
Originally Posted by adam63 Can anyone please help me with that? I need it urgently. Let's see some work. What does the summand simplify to?
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