# Trig substitution

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• May 5th 2010, 03:58 AM
mag6
Trig substitution
• May 5th 2010, 04:09 AM
pickslides
It might become more obvious if you complete the square in the denominator first... (Rofl)
• May 5th 2010, 04:14 AM
mag6
Quote:

Originally Posted by pickslides
It might become more obvious if you complete the square in the denominator first... (Rofl)

if your saying that I use tan substitution then that's not working out....i am at a loss here.. i have an exam and i have been trying to solve this fr some time.....can u explain if u know d answer....
• May 5th 2010, 04:33 AM
pickslides
Try making $\displaystyle x+5 = 5\sec\theta \implies dx = 5\sec\theta \tan\theta$
• May 5th 2010, 04:54 AM
mag6
Quote:

Originally Posted by pickslides
Try making $\displaystyle x+5 = 5\sec\theta \implies dx = 5\sec\theta \tan\theta$

nope....thts not working either....thnx newayz :)
• May 5th 2010, 05:29 AM
mag6
Quote:

Originally Posted by pickslides
Try making $\displaystyle x+5 = 5\sec\theta \implies dx = 5\sec\theta \tan\theta$

thnx tht did work out!