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Math Help - Did I differentiate this incorrectly?

  1. #1
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    Did I differentiate this incorrectly?

    f(x)=(x-1)e^2x

    I used the product rule:

    f'(x) = g'(x)h(x) + g(x)h'(x)

    = (1)(e^2x) + (x-1)(e^2x)(2)

    = e^2x + (2x-2)(e^2x)

    =e^2x [1 + (2x-2)]

    Where did I go wrong? The book answer is: f'(x) = e^2x(2x-1)
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  2. #2
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    Quote Originally Posted by kmjt View Post

    =e^2x [1 + (2x-2)]

    Where did I go wrong? The book answer is: f'(x) = e^2x(2x-1)
    You have the answer, the book just took an extra step

    =e^{2x} [1 + (2x-2)]

    =e^{2x} [1 +2x-2]

     =e^{2x}[2x-1]

     = e^{2x}(2x-1)
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