Find f and a that
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Originally Posted by camherokid Find f and a that 6 + integal_{t=a to x} f(t)/t^2 dt = 2 sqrt(x) 1. When x=a the integral is zero, so: 6 = 2 sqrt(a), or a = 9. 2. Differentiate (by the FTC d/dx[integal_{t=a to x} f(t)/t^2 dt] = f(x)/x^2) f(x)/x^2 = 1/sqrt(x) so: f(x) = x^{3/2}. RonL
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