a little confused on this one
"solve the definite integral"
$\displaystyle \int^2_0 2x^2e^{x^3+5}$
actually, i'm getting really high numbers for this which makes me think i may be doing it wrong.
$\displaystyle \int^2_0 2x^2e^{x^3+5}$
u= $\displaystyle x^3 + 5$
h(u) = $\displaystyle 3x^2$
$\displaystyle \frac{2}{3} \int^2_0 3x^2 e^{x^3+5}$
when x = 0, u = 5
when x = 2, u = 13
$\displaystyle \frac{2}{3} \int^{13}_5 e^u du$
$\displaystyle
\frac{2}{3} e^{13} - \frac{2}{3} e^5$
i'm getting 294,843.32 which makes me think i'm doing something wrong.