a little confused on this one "solve the definite integral"
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Originally Posted by JGaraffa a little confused on this one "solve the definite integral" Well, again, use substitution , which gives that and hence you have
Originally Posted by JGaraffa a little confused on this one "solve the definite integral" What exactly are you confused about? Have you made an attempt at it? Also the integral should be I could tell you how to do it but i think i it's only fair that an attempt is made first Hint: use substitution
ah perfect! i couldn't figure out how i could change that to a . thanks!
actually, i'm getting really high numbers for this which makes me think i may be doing it wrong. u= h(u) = when x = 0, u = 5 when x = 2, u = 13 i'm getting 294,843.32 which makes me think i'm doing something wrong.
Originally Posted by JGaraffa actually, i'm getting really high numbers for this which makes me think i may be doing it wrong. u= h(u) = when x = 0, u = 5 when x = 2, u = 13 i'm getting 294,843.32 which makes me think i'm doing something wrong. No, that result is ok. Of course, is a fast growing function.
Originally Posted by JGaraffa actually, i'm getting really high numbers for this which makes me think i may be doing it wrong. u= h(u) = when x = 0, u = 5 when x = 2, u = 13 i'm getting 294,843.32 which makes me think i'm doing something wrong. Apart from [tex]3x^{2} it lookes fine to me.
Originally Posted by JGaraffa a little confused on this one "solve the definite integral" Again observe that is the derivative of , so consider: CB
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