# Thread: arc length of x= y^4/4 + 1/8y^2

1. ## arc length of x= y^4/4 + 1/8y^2

arc length along the curve x= y^4/4 + 1/8y^2 from y=1 to y =2

please put the steps.

2. Originally Posted by victorxz90044
arc length along the curve x= y^4/4 + 1/8y^2 from y=1 to y =2

please put the steps.
First find the derivative of the curve!

then the arc length will be calculated as:

$L = \int_1^2 \sqrt{1 + (\mbox{derivative})^2} \mbox{ dy}$

,

### x= y^4/4 1/8y^2

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