arc length along the curve x= y^4/4 + 1/8y^2 from y=1 to y =2 please put the steps.
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Originally Posted by victorxz90044 arc length along the curve x= y^4/4 + 1/8y^2 from y=1 to y =2 please put the steps. First find the derivative of the curve! then the arc length will be calculated as: $\displaystyle L = \int_1^2 \sqrt{1 + (\mbox{derivative})^2} \mbox{ dy}$
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