# Thread: arc length of x= y^4/4 + 1/8y^2

1. ## arc length of x= y^4/4 + 1/8y^2

arc length along the curve x= y^4/4 + 1/8y^2 from y=1 to y =2

2. Originally Posted by victorxz90044
arc length along the curve x= y^4/4 + 1/8y^2 from y=1 to y =2

First find the derivative of the curve!

then the arc length will be calculated as:

$\displaystyle L = \int_1^2 \sqrt{1 + (\mbox{derivative})^2} \mbox{ dy}$