# Thread: Help with an equation.

1. Hi

Im Have this equation and I have the result but I canīt get from a to b....

2. Hi

There are several errors in your calculations

At the end of the 1st page there is a + instead of a - inside the square root. So is it in the 2 first equations in the second page

Then you made an error in the second equation of the second page in the simplification by $\alpha$

The right equation is $\beta e^{-\alpha r^V} = \frac{1+\sqrt{1+k_2 \alpha^2}}{k_1 \alpha}$

But I agree with you : the disappearance of $\beta$ is strange

3. Originally Posted by running-gag
Hi

There are several errors in your calculations

At the end of the 1st page there is a + instead of a - inside the square root. So is it in the 2 first equations in the second page

Then you made an error in the second equation of the second page in the simplification by $\alpha$

The right equation is $\beta e^{-\alpha r^V} = \frac{1+\sqrt{1+k_2 \alpha^2}}{k_1 \alpha}$

But I agree with you : the disappearance of $\beta$ is strange
Thank you SOOOOOO MUUUUCH

But what will you get r^v equal to??
Will you devide the right side first with beta and then isolate r^v?

4. Yes, once you have $e^{-\alpha r^V}= \frac{1+\sqrt{1+ k_2\alpha^2}}{\beta k_1\alpha}$, take the logarithm of both sides.
Yes, once you have $e^{-\alpha r^V}= \frac{1+\sqrt{1+ k_2\alpha^2}}{\beta k_1\alpha}$, take the logarithm of both sides.