You already seem to have your answer: namely that the function in polar form is .
I have to express y = 6x^2 in this fashion. here is my work.
y = r sin(theta) = 6x^2
x = r cos(theta) -> x^2 = r^2*(cos(theta))^2
rsin(theta) = 6x^2
rsin(theta) = 6( r^2) (cos(theta))^2
divide both by r...
sin(theta) = 6r (cos(theta))^2
divided the (cos(theta))^2 and the 6 to leave r alone...
(tan(theta)sec(theta))/6 = r
This is the part where i got lost, how do you find theta in this situation?