hey im really dumb,

but is

$\displaystyle (e^{i \pi/4})^ 4 $

=

$\displaystyle e^{i \pi} $

because

$\displaystyle (e^{i \pi/4})^ 4 = e^{4 i \pi/4} $ ?

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- May 3rd 2010, 07:34 PMPengureally dumb question
hey im really dumb,

but is

$\displaystyle (e^{i \pi/4})^ 4 $

=

$\displaystyle e^{i \pi} $

because

$\displaystyle (e^{i \pi/4})^ 4 = e^{4 i \pi/4} $ ? - May 3rd 2010, 07:39 PMsurjectiveGood question
Hello,

Your computation is correct.

And you are not dumb.

(Wink) - May 3rd 2010, 11:58 PMTikoloshe
Congratulations. You have found a fourth root of -1 ($\displaystyle -1=e^{i\pi}$). How many others can you find?