looking for step by step assistance. any help is greatly appreciated find the derivative and compute f`(1) $\displaystyle f(x) = ln(x^2 + 3x + 1) ln(x^3 + 1)$
Follow Math Help Forum on Facebook and Google+
Originally Posted by JGaraffa looking for step by step assistance. any help is greatly appreciated find the derivative and compute f`(1) $\displaystyle f(x) = ln(x^2 + 3x + 1) ln(x^3 + 1)$ What is your attempt so far?
haven't really gotten anywhere with this one, i'm not sure if i should distribute the $\displaystyle ln$ to $\displaystyle (x^2+3x+1)$ and the other $\displaystyle ln$ to $\displaystyle (x^3 +1)$ so confused.
1.use the rule $\displaystyle \left({fg}\right)' = f'g + fg'$ 2. you get $\displaystyle (2x+3)/(x^2+3x+1)ln(x^3+1)+3ln(x^2+3x+1)x^2/(x^3+1)$ 3. compute f'(x=1). You'll get $\displaystyle ln(2)+\frac{3}{2} ln(5)$
View Tag Cloud