if a force of 12 N stretches a Hooke's law spring .20m beyond its natural length, how much work is done by the agent that does the stretching....

please show steps.

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- May 3rd 2010, 05:26 PMvictorxz90044Hooke'sLaw
if a force of 12 N stretches a Hooke's law spring .20m beyond its natural length, how much work is done by the agent that does the stretching....

please show steps. - May 3rd 2010, 05:32 PMskeeter
$\displaystyle F = kx$ ... use the given force and displacement to find the spring constant, $\displaystyle k$ , in Newtons/meter.

work done by a variable force ...

$\displaystyle W = \int_0^L kx \, dx$ , where $\displaystyle L$ = length the spring is stretched or compressed beyond its natural length