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Math Help - Hooke'sLaw

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    Hooke'sLaw

    if a force of 12 N stretches a Hooke's law spring .20m beyond its natural length, how much work is done by the agent that does the stretching....
    please show steps.
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    Quote Originally Posted by victorxz90044 View Post
    if a force of 12 N stretches a Hooke's law spring .20m beyond its natural length, how much work is done by the agent that does the stretching....
    please show steps.
    F = kx ... use the given force and displacement to find the spring constant, k , in Newtons/meter.

    work done by a variable force ...

    W = \int_0^L kx \, dx , where L = length the spring is stretched or compressed beyond its natural length
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