if a force of 12 N stretches a Hooke's law spring .20m beyond its natural length, how much work is done by the agent that does the stretching....
please show steps.
$\displaystyle F = kx$ ... use the given force and displacement to find the spring constant, $\displaystyle k$ , in Newtons/meter.
work done by a variable force ...
$\displaystyle W = \int_0^L kx \, dx$ , where $\displaystyle L$ = length the spring is stretched or compressed beyond its natural length