Evaluate the definite integral. I really am not sure how to evaluate this integral. Do i use the substitution method and set my u = 1+2x?
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Try $\displaystyle x=\frac{u^2}2 -\frac1{\color{red}2}$. edit: whoops. Thanks Linnus.
Last edited by maddas; May 2nd 2010 at 01:48 PM.
[quote=maddas;505552]Try [tex]x=\frac{u^2}2 -1 how did you get that x value?
Wouldn't it be $\displaystyle u= \sqrt{1+2x} $ $\displaystyle u^2=1+2x $ $\displaystyle u^2-1=2x $ $\displaystyle x= (u^2-1)/2 $
[QUOTE=rhcp1231;505555] Originally Posted by maddas Try [tex]x=\frac{u^2}2 -1 how did you get that x value? I chose it so that the square root on the bottom would disappear, ie I wanted 1+2x = u^2. But like Linnus pointed out, I lost the 1/2. heh.
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