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**11rdc11** $\displaystyle \Sigma_{n=2}^\infty \frac{(-1)}{\ln(n)}^2$. I have to decide if the series is abs convergent, cond conv, or div. I think it is abs convergent because if if i take the abs value i end up with a p series. Is this correct?

Also I'm not sure how to approach this problem

$\displaystyle \Sigma_{n=1}^{\infty} \frac{sin(\frac{1}{n})}{n}$

I know the sequence converges to 0 but not sure how to go about testing if the series converges or diverges. I thought about using the comp test but I'm not able to use it. Any suggestions would be appreciated, thanks.