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- May 1st 2010, 06:54 AM #1

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- Mar 2010
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- 60

## sin(x)=cos(2x)

Hi

Again I have to find the point of intersection of these two functions.

I know cos(2x) = cos(x)^2-sin(x)^2

But still: sin(x)=cos(x)^2-sin(x)^2, i have no idea how to solve that. I reached the point (1+sin(x))=tan(x)cos(x), but i don't get further. Anybody who can help to find the exact solution?

- May 1st 2010, 07:23 AM #2

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- Sep 2008
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- West Malaysia
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- May 1st 2010, 07:26 AM #3

- May 1st 2010, 07:35 AM #4

- Joined
- Mar 2006
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- 46

- May 1st 2010, 07:40 AM #5

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- Mar 2010
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- May 1st 2010, 03:47 PM #6