Results 1 to 6 of 6

- May 1st 2010, 07:54 AM #1

- Joined
- Mar 2010
- Posts
- 60

## sin(x)=cos(2x)

Hi

Again I have to find the point of intersection of these two functions.

I know cos(2x) = cos(x)^2-sin(x)^2

But still: sin(x)=cos(x)^2-sin(x)^2, i have no idea how to solve that. I reached the point (1+sin(x))=tan(x)cos(x), but i don't get further. Anybody who can help to find the exact solution?

- May 1st 2010, 08:23 AM #2

- Joined
- Sep 2008
- From
- West Malaysia
- Posts
- 1,261
- Thanks
- 1

- May 1st 2010, 08:26 AM #3

- May 1st 2010, 08:35 AM #4

- Joined
- Mar 2006
- Posts
- 46

- May 1st 2010, 08:40 AM #5

- Joined
- Mar 2010
- Posts
- 60

- May 1st 2010, 04:47 PM #6