given that the cylinder has the equation x^2 +y^2 =ax where a is a constant. Why is the radius of this cylinder in polar coordinates?

Results 1 to 3 of 3

- May 1st 2010, 07:42 AM #1

- Joined
- Aug 2009
- Posts
- 639

- May 1st 2010, 08:43 AM #2

- Joined
- Oct 2009
- Posts
- 4,261
- Thanks
- 3

- May 1st 2010, 09:23 AM #3

- Joined
- Aug 2009
- Posts
- 639

this is part of the range of an integral question and the answer was to integral the question where the radius runs from 0 to acos ( delta) and im wondering why that is the case.

the full question is here:

find the surface area of a hemisphere of a radius a cut off by a cylinder having the radius as diameter where the equation of the cylinder is x^2 +y^2 =ax.