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  1. #1
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    given that the cylinder has the equation x^2 +y^2 =ax where a is a constant. Why is the radius of this cylinder in polar coordinates?
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  2. #2
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    Quote Originally Posted by alexandrabel90 View Post
    given that the cylinder has the equation x^2 +y^2 =ax where a is a constant. Why is the radius of this cylinder in polar coordinates?

    x^2+y^2=ax\iff \left(x-\frac{a}{2}\right)^2+y^2=\frac{a^2}{4} , so the cylinder's radius, in any coordinates, is \frac{a}{2} ...what do you mean "in polar coordinates"?

    Tonio
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  3. #3
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    this is part of the range of an integral question and the answer was to integral the question where the radius runs from 0 to acos ( delta) and im wondering why that is the case.

    the full question is here:
    find the surface area of a hemisphere of a radius a cut off by a cylinder having the radius as diameter where the equation of the cylinder is x^2 +y^2 =ax.
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