Evaluate the iterated integral by converting to polar coordinates.
integral(0,a)integral(-sqrt(a^2-y^2), 0) x^2y dxdy
I transfered the x^2y into polar coordinates:
x= rcos(theta) , y= rsin(theta)
but, i'm not sure how to transform the integral boundaries into polar coordiantes. Usually the first one would be like 0-pi but i'm not sure with the a being there. The a is throwing me off.