y= e^x / 4+ln2x find the derivative at x=1, f'(1)
Last edited by john-1; April 30th 2010 at 03:17 PM.
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Originally Posted by john-1 y=e^x/ (1+lnx) y' at x= 1 = 0 Can someone confirm this for me? Standard quotient rule No idea what your condition means, I'm guessing y'(1) = 0 Hence Note that . To find a co-ordinate sub in x=1 into y (not y') so we have the co-ordinate (1,e) You can now use the equation of a straight line which is
find the derivative at x=1, f'(1) I ended up getting 0.
Last edited by john-1; April 30th 2010 at 03:15 PM.
Originally Posted by john-1 find the derivative at x=1, f'(1) I ended up getting 0. Which is wrong, did you use e^(i*pi)'s expression for the derivative? If not what did you use. CB
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