Determine the equation of the tangent to the graph of y=log(lnk).
just can someone confirm this plz
Last edited by john-1; May 2nd 2010 at 07:03 AM.
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Your solution for the equation of the tangent line is correct. The -intercept is the value of when . In our case,
Hope this helps!
so then how do i solve for k?
because the x is there
Originally Posted by john-1 so then how do i solve for k? hi
kx - ln k -1=0
so k would be k<0 or k>1/e
but k<0 is not acceptable because ln (<0) is undefined .
Do the same to determine the set of values of k so that x is negative .
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