Thread: Differentiating exponential and logarithmic functions

Determine the equation of the tangent to the graph of y=log(lnk).

My answer:

1/(lnkln10)

just can someone confirm this plz

Your solution for the equation of the tangent line is correct. The -intercept is the value of when . In our case,



Hope this helps!

so then how do i solve for k?

because the x is there

Originally Posted by john-1

so then how do i solve for k?

hi

kx - ln k -1=0



so k would be k<0 or k>1/e

but k<0 is not acceptable because ln (<0) is undefined .

Do the same to determine the set of values of k so that x is negative .