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**Archduke01** lim as 2 approaches infinity $\displaystyle \int_2^{inf} e^{-1.9x} dx$

the limit of integration infinity becomes b, and you have to apply the FTC to determine whether it's convergent/divergent etc.

My answer for the integration alone is $\displaystyle -1.9e^{-1.9x}$. When I replace the x by 2 and evaluate, I get -0.0425. However I don't know what to do when doing the same thing with B as my value.

This is what I'm left with; lim as 2 approaches infinity $\displaystyle -1.9e^{-1.9b} - 0.0425$

How can I follow this up?