If CAS are allowed:
Function calculator
I'm having trouble integrating this arc length.
General formula:
, between intervals a and b
My function: , where a=0.00183
So
Putting this derivative into general formula:
, between the intervals of 176.3 and -176.3. (I haven't put a=0.00183 in yet because it would get too messy intergrating it.)
I don't know how to integrate this because I think it involves some method of substitution which I don't know. Any help would be great ;D
If CAS are allowed:
Function calculator
Whenever you have 1+x^2 or 1-x^2 under the square root in an integral it would be a good idea to try some sort of trig substiution using either
sin^2 +cos^2=1
or
cosh^2-sinh^2=1
in this case of course you would use the hyperbolic identity.
express 2ax=cosh(t)
calculate the derivative and make the substitution.
you should end up with
(1/2a) int (sinh^2)
express that in terms of e^x and its easy enough to integrate.