If CAS are allowed:
I'm having trouble integrating this arc length.
, between intervals a and b
My function: , where a=0.00183
Putting this derivative into general formula:
, between the intervals of 176.3 and -176.3. (I haven't put a=0.00183 in yet because it would get too messy intergrating it.)
I don't know how to integrate this because I think it involves some method of substitution which I don't know. Any help would be great ;D
Whenever you have 1+x^2 or 1-x^2 under the square root in an integral it would be a good idea to try some sort of trig substiution using either
in this case of course you would use the hyperbolic identity.
calculate the derivative and make the substitution.
you should end up with
(1/2a) int (sinh^2)
express that in terms of e^x and its easy enough to integrate.