i got : -2(5x +25/4)^-1/2 from 0 to 4 , is it rite??
Almost but not quite.
Let u= 5x+ 25/4. Then du= 5dx so that dx= (1/5)du and the integral is . You don't have the "1/5" and the integral of is [tex](2/3)u^{3/2}[/itex]. It looks like you differentiated rather that integrating.
Let u= 5x+ 25/4. Then du= 5dx so that dx= (1/5)du and the integral is . You don't have the "1/5" and the integral of is [tex](2/3)u^{3/2}[/itex]. It looks like you differentiated rather that integrating.
ok i have it now and i have this
1/5 int 2/3u^(3/2) => 1/5(2/3(5x+25/4)^3/2) |from 0 to 4
answer: 15.8! is this rite?