Find the area that encloses. r = 2 + cos(2θ) For finding the interval I put r = 0. Now I dont know how to solve for r. I am stuck. Any help thx
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Integrate $\displaystyle \frac12r(\theta)^2$ with respect to theta over [0,2pi].
Originally Posted by Tinyboss Integrate $\displaystyle \frac12r(\theta)^2$ with respect to theta over [0,2pi]. how do you get [0,2pi] ?
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