radioactive decay word problem

**yoman360** · April 28th 2010, 03:37 PM

After t years, $50e^{-0.015t}$ pounds of a deposit of a radioactive substance remain. The average amount per year not lost by radioactive decay during the second hundred years is
(A) 2.9 lb
(B) 5.8 lb
(C) 7.4 lb
(D) 11.1 lb
(E) none of these

if it helps the answer is B but i need help how to get that answer

**CaptainBlack** · May 3rd 2010, 12:00 AM

Originally Posted by yoman360

After t years, $50e^{-0.015t}$ pounds of a deposit of a radioactive substance remain. The average amount per year not lost by radioactive decay during the second hundred years is
(A) 2.9 lb
(B) 5.8 lb
(C) 7.4 lb
(D) 11.1 lb
(E) none of these

if it helps the answer is B but i need help how to get that answer

The mass remaining at time $t$ is:

$m(t)=50e^{-0.015t}$

The amount lost between $t_1$ and $t_2$ is:

$M(t_1,t_2)=m(t_1)-m(t_2)$

So the average loss per year is:

$A(t_1,t_2)=M(t_1,t_2)/(t_2-t_1)$

CB

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