e^(xy) = x - y
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With respect to which variable? :3 For x its $\displaystyle (y + x\dot{y})e^{xy} = 1 - \dot{y}$.
Looking for Dy/dx, the book lists the answer as: (y(y-e^(xy))/(y^2-xe^(xy)) Typo lol meant for the "9" to be a ( D:
Last edited by Neversh; Apr 28th 2010 at 03:12 PM.
Does it? I must disagree. Where would the 9 comes from anyway? edit: okay, there's still a typo because your parentheses aren't balanced. But the solution should be $\displaystyle \dot{y} = {1-ye^{xy}\over 1+xe^{xy}}$.
Last edited by maddas; Apr 28th 2010 at 03:20 PM.
Originally Posted by maddas Does it? I must disagree. Where would the 9 comes from anyway? Was a typo :P
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