e^(xy) = x - y

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- Apr 28th 2010, 02:16 PMNevershImplicit Differentiation
e^(xy) = x - y

- Apr 28th 2010, 02:42 PMmaddas
With respect to which variable? :3

For x its $\displaystyle (y + x\dot{y})e^{xy} = 1 - \dot{y}$. - Apr 28th 2010, 03:02 PMNeversh
Looking for Dy/dx, the book lists the answer as: (y(y-e^(xy))/(y^2-xe^(xy))

Typo lol meant for the

"9" to be a ( D: - Apr 28th 2010, 03:08 PMmaddas
Does it? I must disagree. Where would the 9 comes from anyway?

edit: okay, there's still a typo because your parentheses aren't balanced. But the solution should be $\displaystyle \dot{y} = {1-ye^{xy}\over 1+xe^{xy}}$. - Apr 28th 2010, 03:19 PMNeversh