Solid inside x^2+y^2+z^2=16 and outside z= sqrt (x^2+y^2)

Here is what I have so far.

0<r<2sqrt(2)

0<theta<2pi

R<z< sqrt (16-R^2)

Is that the right set up?

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- Apr 28th 2010, 02:21 PMasdf122345Cylindricate Coordinates to find the volume.
Solid inside x^2+y^2+z^2=16 and outside z= sqrt (x^2+y^2)

Here is what I have so far.

0<r<2sqrt(2)

0<theta<2pi

R<z< sqrt (16-R^2)

Is that the right set up?