I am just a little confused by the wording of this problem and I am hoping that someone might have a better idea of how to go about solving this.

Suppose that $\displaystyle \int\int_{D}f(x,y) dA= 3$ where D is the disk $\displaystyle x^2 + y^2 \leq 1$. Now suppose that E is the disk $\displaystyle x^2 + y^2 \leq 4$ and $\displaystyle g(x,y) = 3f(\frac{x} {2}, \frac{y} {2})$. What is the value of $\displaystyle \int\int_{E}g(x,y)dA$?

I am still trying to figure out how to do transformations, so the first thing I did was define two variables and solved for x and y:

$\displaystyle u = \frac{x} {2} and v = \frac{y} {2} \rightarrow 2u = x and 2v = y$

The Jacobian that I found from this ended up being $\displaystyle 4dudv$ but I am not sure where to go from here but this is what I attempted:

$\displaystyle x^2 + y^2 \leq 4 \rightarrow (2u)^2 + (2v)^2 \leq 4 \rightarrow u^2 + v^2 \leq 1 \rightarrow u = + or - \sqrt{1^2-v^2}$

This is about as far as I am right now. I am uneasy about whether this is even right so far and how to set up this integral. Thanks for the help ahead of time, I appreciate it.